Lists and Patterns

Pattern discrimination allows to decompose lists:

let l = [6, 5, 3, 2]

mySum [] = 0
mySum (x:xs) = x + sum xs

mySum l
-- 16

We are recursively calling sum. x = first element xs = tail list (rest of the list)

Having fun? Other ways to do it:

• With a fold:

mySum = foldr (+) 0

• With a List Comprehension:

mySum xs = sum [x | x <- xs]

We say that e1 matches e2 if there exists a substitution for the variables of e1 that make it the same as e2.

Examples:

• x:xs matches [2, 5, 8] because [2, 5, 8] is 2 : (5 : 8 : []) substituting x with 2 and xs with (5 : 8 : []) which is [5, 8].
• x:xs does not match [] because [] and : are different constructors.

  That's because x cannot be a list, it has to be an element inside the list.

• x1:x2:xs matches [2, 5, 8] substituting x1 with 2, x2 with 5 and xs with [8].
• x1:x2:xs matches [2, 5] substituting x1 with 2, x2 with 5 and xs with [].

Note: The mechanism of matching is not the same as the unification (Prolog).